在openwrt上运行gost 报错查了半天搞不定，特来求助

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#!/bin/sh /etc/rc.common
START=90
STOP=10
enable="$(uci -q get gost.arguments.enable)"
prog_path="$(uci -q get gost.arguments.path)"
configure_file="$(uci -q get gost.options.configure_file)"
prog=`basename $prog_path`
start()
{
["x${enable}" != "xtrue" ] && exit 0
pid=`ps | grep -v grep | grep -v etc | grep -i "$prog" | awk ‘{print $1}’`
if ["x$pid" == "x"]; then
    $prog_path -C $configure_file 2>&1 > /var/log/$prog.log &
    echo -e "n$prog started!n"
else
    ## program is running, exit with error.
    echo -e "nError! $prog is currently running!n" 1>&2
    exit 1
fi
}
stop() {
pid=`ps | grep -v grep | grep -v etc | grep -i "$prog" | awk ‘{print $1}’`
if ["x$pid" == "x"]; then
    ## Program is not running, exit with error.
    echo -e "nError! $prog not started!n" 1>&2
    exit 1
else
    ## Program is running, so stop it
    kill -15 $pid
    echo -e "n$prog stopped!n"
fi
}
restart() {
    stop
    start
}
复制代码
报如下错误
/etc/rc.common: /etc/init.d/gost: line 20: syntax error: unexpected "then" (expecting "}") 复制代码我看不出来有语法错误啊